OT: Requesting C advice

[Mike McCarty]

Andy Green wrote:
> Michael Hennebry wrote:
> 
> 
>>>printf("%d\n",-2);
>>>
>>>does not result in
>>>
>>>-2
>>
>>It should.
>>printf, declared or not, will look for an int and get it.
>>
>>printf("%u\n", -2);
>>is more interesting.
> 
> 
> That will do exactly the same on big and little-endian machines too, if
> the int size is the same.

Yes, of course. I gave a bad example. But, if one uses different sized
print formats from those in the int, it can do what I wrote...

printf("%d\n",(long int)-2);

can print

-1

for example, on a big-endian machine.

Mike
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