Re: Bug in my shell script

["Pete Peterson" <petersonp genrad com>]

> From guinness-list-admin@redhat.com  Thu Mar 29 15:16:13 2001
> Delivered-To: guinness-list@listman.redhat.com
> From: "Jasper Jans" <jjans@bio.vu.nl>
> To: <guinness-list@redhat.com>
> Subject: Bug in my shell script
> 
> Hi..
> 
> I'm trying to write a shell script but for some reason I cannot
> get it to work.. can anyone be so good to tell me what is going
> wrong here?
> 
> ---
> #!/bin/sh -x
> 
> if [ $# -eq 0 ]; then
>         echo "Usage: $0 <expression>";
>         exit;
> fi
> 
> echo "find /home/guests/jjans -type d -name '*"$1"*' -exec 'sed s/*.sts//g'
> \;" | sh

I think you just want:
find /home/guests/jjans -type d -name \*$1\* -print | sed 's%/^home/guests%%'

You don't really need the -print, since that's a default, but I usually
include it out of habit.

You don't need the "g" on the sed pattern in this case, since there
would only be one match per line.

I think it's better to be more specific in the pattern match -- there
could be an "sts" somewhere farther along in the line and then you'd
zap everything before that. Consider:
    /home/guests/jjans/Projects/A/costs/estimates
With just looking for "sts", you'd end up with
     /estimates
instead of
     /jjans/Projects/A/costs/estimates

The "^" in the pattern also helps avoid 'surprises'.

Note that I piped the output of 'find' into 'sed'.  It appears that
your way would try to run sed on the directory itself, rather than
on the list of names.  I suspect that sed wouldn't like that.

> ---
> 
> I call this like: ./bla.sh roje
> And the find part (if I run that seperately) returns lines like:
> /home/guests/jjans/Projects/A
> /home/guests/jjans/Projects/B
> etc..
> 
> The sed part is support to strip of the /home/guests part and make it
> such that the output is
> /jjans/Projects/A
> /jjans/Projects/B
> etc..
> 
> However when I run this I get absolutely no output at all..
> Anyone?
> 
> Thanks,
> J.


        pete peterson
        GenRad, Inc.
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