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How to remove an i686 pkg without touching x86_64 one?



Thanks.  I had tried a -q --whatrequires using that technique and it didn't 
work.  But indeed, rpm -e --test glibc.i686 did work great.

Thanks!

Eric

"Matthias Saou" 
<thias spam spam spam spam spam spam spam egg and spam freshrpms net> wrote 
in message news:20060322105848 7ace7edb python2   
> Eric B. wrote :
>
>> I've got an RHEL4 x86_64 system that I installed a while ago.  I was 
>> doing
>> some maintenance on it, and noticed that I had two different versions of
>> glibc installed: glibc.i686 and glibc.x86_64.  The only way I am able to 
>> see
>> the difference between the packages is using rpm -q --query --queryformat
>> %{ARCH} glibc.
>>
>> I would like to either remove the i686 version of glibc or at the very 
>> least
>> see which pkgs depend upon it.  How can I check the dependencies on the 
>> i686
>> pkg or remove the specific i686 package without touching the x86_64 one?
>
> Just do :
>
> rpm -e glibc.i686
>
> ...and you'll see everything that depends on it ;-)
>
> Matthias
>
> -- 
> Clean custom Red Hat Linux rpm packages : http://freshrpms.net/
> Fedora Core release 5 (Bordeaux) - Linux kernel 2.6.15-1.2054_FC5
> Load : 0.74 0.64 0.63 




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