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Re: how to calculate correct values for resize2fs



Hello Jelle

1. Please don't CC to poster if you answer, we are all on this list and
   get the messages anyways.

2. And please don't full-quote if not *really* necessary.

3. From your other mail:
   > The problem is I have to automate this process
   That's an important information you forgot to mention in the initial
   post ;)

* Jelle de Jong <jelledejong powercraft nl> hat geschrieben:

> $ fdisk -l /dev/sda
> Disk /dev/sda: 4034 MB, 4034838528 bytes

> bc <<< "4034-16"
> resize2fs /dev/sda1 4018M
> 
> # result: partition is only 983973 (4K) blocks
> # requested: 1028608 blocks
> # will not fit exiting

4034838528 is 3847 MB and not 4034 like fdisk told you. Obviously fdisk is 
using that bogus SI-numbering.

4018*1024^2 is 1028608 clusters and the underlaying block device of the 
file system only supports 983973 clusters (which it already provides).

So: Take the bytes value, devide it by 1024^2 to gain the real number of
MBs and subtract 18 (not 16) MB in the first call to resize2fs like this:

resize2fs -p /dev/sda1 $(echo "
	scale=0;
	$(
		export LANG=C
		fdisk -l /dev/sda | grep sda: | awk '{ print $5 }'
	)/1024^2-18
" | bc)

Then shrink the partition by 16 MB then resize2fs /dev/sda1 without
argument again to fill up the unused space again.

Remember my advice from the previous mail I'v written as well.

Regards, Bodo


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