Les Mikesell wrote: ```edwardspl ita org mo wrote: ``` ```chmod g+rwx ( What number of g+rwx, eg : ?77 ) /home/edward ``` ```You can use the symbolic form literally. I think it's easier to understand. Let the computer do the binary/octal math. g+rwx means add the read, write, and execute bits for the group. ``` ```But I want to know what no of g+rwx... ``` ``` The + means it is added to the bits already permitted. Look at them as groups of 3 bits in binary and take the octal value. user group other rwx rwx rwx You'll start with a home dir having rwx --- --- so that's 111 000 000 binary or 700 octal. Add the group rwx and you get 111 111 000 or 770 octal ``` So, g+rwx = 770, right ? ```chmod +t ( What number of +t ) /home/edward ``` ``` That's one more bit to the left, 1 000 000 000 binary, so 1000 octal. Add that to what you have. ``` ```Same here, you can type it that way and it means add the "sticky" bit. ``` ```Also want to know... ``` ``` Altogether, the octal value for the mode ends up at 1770. But, as I said before the computer does a better job of thinking in octal. ``` So, +t = 1770, right ? Edward.