bash question

[Jacques B.]

On 10/31/07, Jacques B. <jjrboucher at gmail.com> wrote:
> On 10/31/07, Dario Lesca <d.lesca at solinos.it> wrote:
> > In this shell script:
> >
> > > #!/bin/bash
> > > i=0
> > >
> > > printf "a a a\nb b b\nc c c\n" |
> > > while read x
> > > do
> > >         i=$[i+1]
> > >         echo "$x: ($i)"
> > > done
> > >
> > > echo $i
> >
> > with this output:
> >
> > > a a a: (1)
> > > b b b: (2)
> > > c c c: (3)
> > > 0
> >
> > How to I can get the value (3) for $i out of the while loop?
> >
> > Many thanks
> >
> > --
> > Dario Lesca <d.lesca at solinos.it>
>
> Is there a  reason for using while instead of for?
>
> for x in $(ls dir/)
> do
>    .....
> done
>
> Jacques B.
>

The one caution when dealing with path/filenames is spaces.  That was
discussed not long ago and a few suggestions were given, mine being to
change the $IFS variable but others were suggested that also worked if
I recall.

Jacques B.