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Re: Sed programming question




Dan Thurman wrote:
> Kevin Martin wrote:
>>
>> Gordon Messmer wrote:
>>  
>>> Dan Thurman wrote:
>>>    
>>>> I tested your suggestion above with and without -r option
>>>> but could not make it work as an "AND operator":
>>>>
>>>> # echo "foo har" | sed -re '/foo/{/bar/{s/foo/goo/}}'
>>>> goo har
>>>>       
>>> $ rpm -q sed
>>> sed-4.1.5-11.fc10.x86_64
>>>
>>> $ echo "foo har" | sed -re '/foo/{/bar/{s/foo/goo/}}'
>>> foo har
>>>
>>>     
>>
>> $ echo "foo har"  | sed -e "s/foo/goo/g" -e "s/har/bar/g"
>> goo bar
>>
>> Is this what you're trying to do?
>>
>> Kevin
>>   
> No.  The result should be: (foo AND har) = (1&0)=0
> so the inside nested brackets should not be allowed to
> run and the original string (foo har) is returned.
>
> Dan
>
Ah, I missed the first part of the conversation where it was explained
what you were doing (ah, snipped mail).  Sorry for butting in.

Kevin


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