VSFTPD confusion

[Mike Klinke]

All, 

The /etc/init.d/startup file seems to equate the command to start up 
as "/usr/sbin/vsftpd vsftpd &" according to the way the pathname is 
parsed in the script below.  However, the filename in /etc/vsftpd 
is named "vsftpd.conf" not "vsftpd" and it therefore doesn't start 
properly when passed as an argument in the script in my system.

Code snippet from from /etc/init.d/vsftpd

        if [ -d /etc/vsftpd ] ; then
                for i in `ls /etc/vsftpd/*.conf`; do
                        site=`basename $i .conf`
                        echo -n $"Starting $prog for $site: "
                        /usr/sbin/vsftpd $i &
                        RETVAL=$?
                        [ $RETVAL -eq 0 ] && {
                           touch /var/lock/subsys/$prog
                           success $"$prog $site"
                        }
                        echo
                done

Using this I can't seem to start vsftpd with the default 
configuration by using the command "/etc/init.d/vsftpd start". A 
"ps aux" shows that it didn't start and when I tried this at the 
command line I, understandably, get an error as follows:

08:41:10 # for i in `ls /etc/vsftpd/*.conf`; \
           do site=`basename $i .conf`; \
          `/usr/sbin/vsftpd $site`; done

500 OOPS: vsftpd: cannot open config file:vsftpd

I filed this as a bug:

https://bugzilla.redhat.com/bugzilla/show_bug.cgi?id=136047

but got a response "WORKSFORME" and it was subsequently closed.  I'm 
obviously missing something, so ... how can this possibly work?

Regards, Mike Klinke