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Re: [libvirt] [PATCH] docs: Load libvirt_access*.xml from build dir

On 09/20/2013 08:16 AM, Jiri Denemark wrote:

>> +++ b/docs/Makefile.am
>> @@ -242,6 +242,7 @@ internals/%.html.tmp: internals/%.html.in subsite.xsl page.xsl sitemap.html.in
>>  html/index.html: libvirt-api.xml newapi.xsl page.xsl sitemap.html.in
>>  	$(AM_V_GEN)if [ -x $(XSLTPROC) ] ; then \
>>  	  $(XSLTPROC) --nonet -o $(srcdir)/ \
>> +	  --stringparam builddir $(abs_top_builddir) \

The makefile populates it without ''...

>> +  <xsl:param name="builddir" select=".."/>

as does your default...

> Oh, actually, the above should have been select="'..'" as this is a
> string parameter. It should only matter when someone calls xsltproc by
> hand as the Makefile always overrides the default value.

>>    <xsl:variable name="acls">
>> -    <xsl:copy-of select="document('../src/libvirt_access.xml')/aclinfo/api"/>
>> +    <xsl:copy-of select="document('{$builddir}/src/libvirt_access.xml')/aclinfo/api"/>

and you are expanding {$builddir} _within_ a '' context.  I'm assuming
that as written, it expands to ('../src/...'), but if builddir is
defined with "'..'", it would expand to (''..'/src/...').  So what am I
missing (probably a misunderstanding on my part about how xslt variable
expansion works)?

Eric Blake   eblake redhat com    +1-919-301-3266
Libvirt virtualization library http://libvirt.org

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