[lvm-devel] [PATCH 2/3] Revert "Add a regex optimisation pass for shared character prefixes."
Zdenek Kabelac
zkabelac at redhat.com
Thu Apr 22 13:29:03 UTC 2010
This reverts commit 23dd4773d4decbe564090430e8d82eea1198344c.
Signed-off-by: Zdenek Kabelac <zkabelac at redhat.com>
---
WHATS_NEW_DM | 1 -
libdm/regex/parse_rx.c | 180 ++----------------------------------------------
2 files changed, 5 insertions(+), 176 deletions(-)
diff --git a/WHATS_NEW_DM b/WHATS_NEW_DM
index c96260c..60725a8 100644
--- a/WHATS_NEW_DM
+++ b/WHATS_NEW_DM
@@ -1,6 +1,5 @@
Version 1.02.47 -
=================================
- Add a regex optimisation pass for shared character prefixes.
Add dm_bit_and and dm_bitset_equal to libdevmapper.
Simplify dm_bitset_create.
Speed up dm_bit_get_next with ffs().
diff --git a/libdm/regex/parse_rx.c b/libdm/regex/parse_rx.c
index fb8b886..fdea1a3 100644
--- a/libdm/regex/parse_rx.c
+++ b/libdm/regex/parse_rx.c
@@ -329,182 +329,19 @@ static struct rx_node *_or_term(struct parse_sp *ps)
return n;
}
-/*----------------------------------------------------------------*/
-
-/*
- * The optimiser spots common prefixes on either side of an 'or' node, and
- * lifts them outside the 'or' with a 'cat'.
- */
-static unsigned _leftmost_depth(struct rx_node *r)
-{
- int count = 1;
-
- while (r->type != CHARSET) {
- count++;
- r = r->left;
- }
-
- return count;
-}
-
-/*
- * FIXME: a unique key could be built up as part of the parse, to make the
- * comparison quick. Alternatively we could use cons-hashing, and then
- * this would simply be a pointer comparison.
- */
-static int _nodes_equal(struct rx_node *l, struct rx_node *r)
-{
- if (l->type != r->type)
- return 0;
-
- switch (l->type) {
- case CAT:
- case OR:
- return _nodes_equal(l->left, r->left) &&
- _nodes_equal(l->right, r->right);
-
- case STAR:
- case PLUS:
- case QUEST:
- return _nodes_equal(l->left, r->left);
-
- case CHARSET:
- return dm_bitset_equal(l->charset, r->charset);
- }
-
- /* NOTREACHED */
- return_0;
-}
-
-static int _find_leftmost_common(struct rx_node *or,
- struct rx_node **l,
- struct rx_node **r)
-{
- struct rx_node *left = or->left, *right = or->right;
- unsigned left_depth = _leftmost_depth(left);
- unsigned right_depth = _leftmost_depth(right);
-
- while (left_depth > right_depth) {
- left = left->left;
- left_depth--;
- }
-
- while (right_depth > left_depth) {
- right = right->left;
- right_depth--;
- }
-
- while (left_depth) {
- if (left->type == CAT && right->type == CAT) {
- if (_nodes_equal(left->left, right->left)) {
- *l = left;
- *r = right;
- return 1;
- }
- }
- left = left->left;
- right = right->left;
- left_depth--;
- }
-
- return 0;
-}
-
-static struct rx_node *_pass(struct dm_pool *mem,
- struct rx_node *r,
- int *changed)
-{
- /*
- * walk the tree, optimising every 'or' node.
- */
- switch (r->type) {
- case CAT:
- if (!(r->left = _pass(mem, r->left, changed)))
- return_NULL;
-
- if (!(r->right = _pass(mem, r->right, changed)))
- return_NULL;
-
- break;
-
- case STAR:
- case PLUS:
- case QUEST:
- if (!(r->left = _pass(mem, r->left, changed)))
- return_NULL;
- break;
-
- case OR:
- /* It's important we optimise sub nodes first */
- if (!(r->left = _pass(mem, r->left, changed)))
- return_NULL;
-
- if (!(r->right = _pass(mem, r->right, changed)))
- return_NULL;
-
- {
- struct rx_node *left, *right;
-
- if (_find_leftmost_common(r, &left, &right)) {
- struct rx_node *new_r = _node(mem, CAT, left->left, r);
-
- if (!new_r)
- return_NULL;
-
- memcpy(left, left->right, sizeof(*left));
- memcpy(right, right->right, sizeof(*right));
-
- r = new_r;
-
- *changed = 1;
- }
- }
- break;
-
- case CHARSET:
- break;
- }
-
- return r;
-}
-
-static struct rx_node *_optimise(struct dm_pool *mem, struct rx_node *r)
-{
- /*
- * We're looking for (or (... (cat <foo> a)) (... (cat <foo> b)))
- * and want to turn it into (cat <foo> (or (... a) (... b)))
- */
-
- /*
- * Initially done as an inefficient multipass algorithm.
- */
- int changed;
-
- do {
- changed = 0;
- r = _pass(mem, r, &changed);
- } while (r && changed);
-
- return r;
-}
-
-/*----------------------------------------------------------------*/
-
struct rx_node *rx_parse_tok(struct dm_pool *mem,
const char *begin, const char *end)
{
struct rx_node *r;
struct parse_sp *ps = dm_pool_zalloc(mem, sizeof(*ps));
- if (!ps)
- return_NULL;
-
- ps->mem = mem;
- if (!(ps->charset = dm_bitset_create(mem, 256))) {
- log_error("Regex charset allocation failed");
- dm_pool_free(mem, ps);
+ if (!ps) {
+ stack;
return NULL;
}
+
+ ps->mem = mem;
+ ps->charset = dm_bitset_create(mem, 256);
ps->cursor = begin;
ps->rx_end = end;
_rx_get_token(ps); /* load the first token */
@@ -512,13 +349,6 @@ struct rx_node *rx_parse_tok(struct dm_pool *mem,
if (!(r = _or_term(ps))) {
log_error("Parse error in regex");
dm_pool_free(mem, ps);
- return NULL;
- }
-
- if (!(r = _optimise(mem, r))) {
- log_error("Regex optimisation error");
- dm_pool_free(mem, ps);
- return NULL;
}
return r;
--
1.7.0.1
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