Script
Schott, Erik J Mr ANOSC/FCBS
erik.schott-FCBS at NETCOM.ARMY.MIL
Mon Jan 3 21:47:08 UTC 2005
Or you could use
grep truc /etc/hosts | cut -c1-15
-----Original Message-----
From: redhat-list-bounces at redhat.com
[mailto:redhat-list-bounces at redhat.com]On Behalf Of Benjamin J. Weiss
Sent: Monday, January 03, 2005 2:38 PM
To: General Red Hat Linux discussion list
Subject: Re: Script
truc nguyen wrote:
>Hi,
>
>In my hosts file, the last line is as follow
>197.2.23.134 truc TRUC
>
>I want to write a script to get the this IP address.
>What command in sed or awk to execute this ?
>
>Thank you so much
>
>
>
I see that you've gotten a couple of answers already. However, in the
interests of "There's more than one way to do it", here's another approach:
grep truc /etc/hosts | grep -o
"[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}"
or
grep truc /etc/hosts | grep -o "[0-9]*\.[0-9]*\.[0-9]*\.[0-9]*"
or
grep truc /etc/hosts | cut -f1 -d" "
I'm sure that there are others. :)
Ben
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