sort
vipin sagar
sagar.vipin at gmail.com
Tue Jun 20 12:45:40 UTC 2006
Mr.Sean is correct.
...a litle bit from my side...
[vipin at vipin ~]$ grep -v age testsort.txt | awk '{print $2}' | sort -r
On 6/19/06, Miner, Jonathan W (CSC) (US SSA)
<jonathan.w.miner at baesystems.com> wrote:
>
>
> -----Original Message-----
> From: redhat-list-bounces at redhat.com on behalf of Aimin Yan
> Sent: Sat 06/17/2006 02:23 PM
> To: redhat-list at redhat.com
> Cc:
> Subject: sort
>
>
>
> i have a file, I want to sort this file based on the 2nd column, and start
> from 1st row.how can
> I do use sort command to do in redhat linux.
> for example, this is file I want to sort
>
>
> name age income
> trorry 34 344
> aimin 36 345
> shihe 23 3667
>
> Aimin
>
> -----------------------------
>
> Lots of possible answers to this, here is one that preserves the header line, and the rest of the file contents:
>
> f={filename}
>
> (head -1 $f; awk 'BEGIN {getline} {print $0}' $f | sort -k2 -n) > $f.new
>
> mv $f.new $f
>
>
>
> This depends on having a single title line in the field, a better method, in my opinion, is to use the pound sign (#) to mark comments. The code then becomes:
>
> f={filename}
>
> (grep '^#' $f; grep -v '^#' $f | sort -k2 -n) > $f.new
>
> mv $f.new $f
>
>
>
> Enjoy
>
>
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>
--
~O_0~
~sagar
http://vipinsagar.be
...i've to look back when i heard a gong! i could only see a huge
cobweb and its shining, just got wonder, what the time it was…5AgAr
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