Quick question on awk usage
Michael Velez
mikev777 at hotmail.com
Tue Jun 27 15:22:30 UTC 2006
> -----Original Message-----
> From: redhat-list-bounces at redhat.com
> [mailto:redhat-list-bounces at redhat.com] On Behalf Of Bliss, Aaron
> Sent: Tuesday, June 27, 2006 11:03 AM
> To: redhat-list at redhat.com
> Subject: RE: Quick question on awk usage
>
> Sorry, $14 == 528, not $12 (looks like the email client
> wrapped the line
> also)
>
> Aaron
>
> Hi everyone, I have a quick question on using awk from the
> command line; I have a tab delimited file, and would like to
> know the syntax to print the entire line only when $12 ==
> 575; the syntax from the command line to print only $1 would
> be cat security.log | awk '{print $1}' ; any ideas (grepping
> for 578 won't be good enough since it's possible that
> 578 could appear somewhere else in the file) Thanks very much.
>
> Aaron
>
> Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 4
> Security 263985 Sun Jun 25 15:54:02 2006 528
> Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 4
> Security 263985 Sun Jun 25 15:54:02 2006 575
>
>
I believe this should do it:
awk ' $14 == 575 {print $0}'
Michael
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