script problem

[Steven Buehler]

	I have a backup script that I wrote.  In it I have a variable that
has listings of directories to back up.  Because of some of the sizes of the
directories, and for other reasons, they now want me to break them where I
back them up into multiple files with the name of the directory instead of
all in one file.  It would be simple except that I can't find how to get
just the final directory name for each directory.

Example:
DIRSTOBACKUP= "/usr/local/bin
/etc
/home/steve
/usr/local/src"

I can read thru each line of the variable, but unless I use the "split"
function and assign each item in the split, I can't get the last name of the
directory.  How can this be accomplished?  I guess it might be easier to
find a way to just chop off the first "/" and then replace the rest with "_"
and use that as the backup file name.  That way they can also look at the
file name and see what directory it came from if I am able to replace the
"/" characters.  But alas, I am not that great at the regular expression
replacement in a string either.  I have tried:

DIRSTOBACKUP= "/usr/local/bin
/etc
/home/steve
/usr/local/src"

for name in ${DIRSTOBACKUP[@]}
do
NEWNAME=sed "s/\//_/g" < $name
echo $NEWNAME
done


But that doesn't seem to work.  Any ideas?

Thanks
Steve